Longest Palindromic Subsequence
Problem Description here
Problem: একটি স্ট্রিং দেয়া থাকবে। ঐ স্ট্রিং থেকে সর্বোচ্চ কত লেন্থ এর সাবসিকুয়েন্স নেয়া সম্ভব যেটি একটি প্যালিন্ড্রোম হবে?
Solution:
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#include<bits/stdc++.h> | |
using namespace std; | |
string s; | |
int dp[1005][1005]; ///dp[l][r] means maximum length of palindromic subsequence of string s[l..r] | |
int FuN(int lptr,int rptr) | |
{ | |
if(lptr > rptr) | |
return 0; | |
if(lptr == rptr) | |
return 1; | |
if(dp[lptr][rptr] != -1) | |
return dp[lptr][rptr]; | |
int ret1=0,ret2=0; | |
if(s[lptr] == s[rptr]) | |
ret1 = 2 + FuN(lptr+1 , rptr-1); | |
else{ | |
ret1 = FuN(lptr+1 , rptr); | |
ret2 = FuN(lptr , rptr-1); | |
} | |
return dp[lptr][rptr] = max(ret1 , ret2); | |
} | |
int main() | |
{ | |
int i,j,k,n,mx=0; | |
cin>>s; | |
n = (int)s.size(); | |
memset(dp , -1 , sizeof(dp)); | |
for(i=0 ; i<n ; i++){ | |
for(j=i ; j<n ; j++){ | |
mx = max(mx , FuN(i , j)); | |
cout<<i<<' '<<j<<' '<<dp[i][j]<<endl; | |
} | |
} | |
cout<<mx<<endl; | |
return 0; | |
} |
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